Response to : Comment on ( Does the Equivalence between Gravitational Mass and Energy Survive for a Composite Quantum Body ? )

We have recently shown that both passive and active gravitational masses of a composite body are not equivalent to its energy due to some quantum effects. We have also suggested idealized and more realistic experiments to detect the above-mentioned inequivalence for a passive gravitational mass. The suggested idealized effect is as follows. A spacecraft moves protons of a macroscopic ensemble of hydrogen atoms with constant velocity in the Earth’s gravitational field. Due to nonhomogeneous squeezing of space by the field, electron ground state wave function experiences time-dependent perturbation in each hydrogen atom. This perturbation results in the appearance of a finite probability for an electron to be excited at higher energy levels and to emit a photon. The experimental task is to detect such photons from the ensemble of the atoms. More realistic variants of such experiment can be realized in solid crystals and nuclei, as first mentioned by us. In his recent comment on our paper, Crowell has argued that the effect, suggested by us, contradicts the existing experiments and, in particular, astronomic data. We show here that this conclusion is incorrect and based on the so-called “free fall” experiments, where our effect does not have to be observed.


Introduction
I would like to thank Benjamin Crowell for his comment [1] on my article [2].Creation of the so-called Theory of Everything is well known to be one of the most important problems in physics.It is also known that development of the Quantum Gravitation theory is one of the most important steps in this direction.Nevertheless, the latter problem appears to be extremely difficult.One of the reasons for that is the fact that the foundations of General Relativity and Quantum Mechanics are very different.Another reason is the absence of the corresponding experimental data.We recall that, so far, quantum effects have been directly tested only in the Newtonian variant of gravitation (see, e.g., [3,4]).In this complex situation, we have recently suggested two novel phenomena [2,[5][6][7][8][9][10].In particular, we have demonstrated that both passive and active gravitational masses of a composite body are not equivalent to its energy due to some quantum effects.We have also suggested two experimental ways [2,[5][6][7][8][9][10] to test the above-mentioned phenomena.If one of such experiments is done, it will be the first direct observation of quantum effects in General Relativity.

Goal
In his recent comment [1], Crowell criticizes one of the experiments, suggested by us [2], which can demonstrate inequivalence between passive gravitational mass of a composite quantum body and its energy.The idealized variant of the experiment is as follows.There is a macroscopic ensemble of hydrogen atoms with each of them being in ground state at  = 0. Protons of all atoms are dragged by a spacecraft with constant velocity in the Earth's gravitational field.Due to nonhomogeneous squeezing of space by the gravitational field, the atoms are shown [2,[5][6][7][8] to become excited and emit photons.As mentioned in [5], the above described Advances in High Energy Physics phenomenon is very general and have be observed in solids, nuclei, and elementary particles.The main criticism of the experiment [2,[5][6][7][8] in the comment [1] is the statement that the application of our theory to experiments on proton decay is not consistent with the existing experimental data.The goal of our reply is threefold.First, we pay attention that the discussed existing experimental data in [1] are obtained for free falling objects.On the other hand, the idealized experiment, suggested by us [2,[5][6][7][8], corresponds to transportation of centers of masses of the hydrogen atoms (i.e., protons) by spacecraft with a constant velocity.We stress that these are two different types of experiments.Second, to strengthen our arguments, we derive the Hamiltonian for the transportation of a hydrogen atom with constant velocity, semiquantitatively introduced in Refs.[2,[5][6][7][8], from the Dirac equation in a curved space-time of General Relativity.Third, we discuss "free fall" experiments for a hydrogen atom and make the conclusion that the effect, suggested by us for passive gravitational mass [2,[5][6][7][8], does not have to be observed under such conditions.Thus, proton decay does not have to demonstrate our effect in "free fall" experiments too.So, we make a conclusion that, contrary to the statement of the comment [1], the existing experiments on proton decay do not contradict our theoretical results.

Semiquantitative Hamiltonian
First, let us derive the Hamiltonian of [2,[5][6][7][8] for a hydrogen atom in the Earth's gravitational field, using semiquantitative approach.Below, we consider the case of a weak gravitational field; therefore, we can write the standard interval, describing space-time in a weak field approximation [11]: [Here  is the gravitational constant,  is the velocity of light,  is the Earth mass, and  is the distance between its center and proton.]In accordance with General Relativity, we introduce the so-called local proper space-time coordinates, where space coordinates do not depend on time and where the interval (1) has the Minkowski form.
In these local space-time coordinates, we can approximately write the Schrödinger equation for electron in the atom in the standard form, where proton is supposed to have a fixed position due to action of some nongravitational force on it.[Here p = −ℏ/r  ;   and  are electron mass and charge, resp.]Let us discuss the approximation ( 1)-( 3).First, in ( 1), ( 2), we take into account only terms of the order of ||/ 2 , which can be estimated as 10 −9 near the Earth.Second, in (3), we disregard the so-called tidal effects.This means that we do not differentiate gravitational potential, , with respect to electron coordinates, r and r  .In the next section, we estimate the tidal terms in the Hamiltonian, which, as will be shown, are of the order of ( in the Earth's gravitational field.[Here   is a hydrogen atom typical "size" (i.e., Bohr's radius) and  0 is the Earth's radius.]Third, we consider proton as a classical particle with mass   ≫   , whose position is fixed and kinetic energy is negligible.As usual, we treat the weak gravitation (1), ( 2), as a perturbation in the inertial coordinate system, corresponding to the coordinates (, , , ) in (2).By substitution of these coordinates in the Hamiltonian (3), it is easy to obtain the following effective electron Hamiltonian: and to rewrite it in more convenient form: We point out that, in (5), we introduce the following expression for electron passive gravitational mass operator: which is equal to electron weight operator in the weak gravitational field (1).Note that, in (6), the first term is the bare electron mass,   , and the second term corresponds to the expected electron energy contribution to the mass operator, whereas the third term is the nontrivial virial contribution to the gravitational mass operator.We recall that the Hamiltonian ( 5) and ( 6) are derived for the case, where a hydrogen atom center of mass (i.e., proton) has a fixed position with respect to the Earth.In other words, it is supported in gravitational field (1) by some nongravitational force.Now, suppose that the proton is dragged with small and constant (with respect to the Earth) velocity,  ≪ , by a spacecraft, where  is the fine structure constant and  is a characteristic value of electron velocity in a hydrogen atom.In this case, we can use adiabatic approximation, which results in the following time-dependent perturbation for the electron Schrödinger equation [2, 5-8]: Note that we are interested in electron excitations, therefore, in the electron Hamiltonian (7), we keep only the virial term, which does not commute with the Hamiltonian, taken in the absence of gravitational field.Since the Hamiltonian ( 7) is time dependent it causes the appearance of electron excitations and, thus, the appearance of photon emission from a macroscopic ensemble of the atoms.It is important that the Hamiltonians ( 5)-( 7) are not valid for the free falling atoms, where we have to introduce the so-called normal Fermi coordinates [12,13].As a result free falling atoms "feel" only second derivatives of the gravitational potential [12,13].

The Most General Hamiltonian
To strengthen our arguments, in this section, we derive our Hamiltonian ( 5) and ( 6) from the more general Hamiltonian of [14].The latter Hamiltonian [14] is obtained from the Dirac equation in a curved space-time of General Relativity.In [14], completely different physical effect-the mixing effect between even and odd wave functions in a hydrogen atom (i.e., the so-called relativistic Stark effect)-is studied.It is important that it is studied not for the free falling atoms but for the atom, whose center of mass is supported by nongravitational force in the weak gravitational field (1).Note that the corresponding Hamiltonian is derived in 1/ 2 approximation, as in our case.The peculiarity of the calculations in [14] is that not only terms of the order of / 2 are calculated, as in our case, but also terms of the order of   / 2 , where   is a symbolic derivative of  with respect to relative electron coordinates in the atom.Note that, in accordance with the existing tradition, we call the latter terms tidal ones.Obtained in [14], the Hamiltonian (3.24) for the corresponding Schrödinger equation can be expressed as a sum of the following four terms: where [Here, g = −(/ 3 )R.]Let us describe notations in ( 8)- (12).Note that R and P are position and momentum of a center of mass of the atom, correspondingly.On the other hand, r and p are relative electron position and momentum in the center of mass coordinate system;  =     /(  +  ) is the reduced electron mass.As seen from ( 9), Ĥ0 ( P, p, ) corresponds to the Hamiltonian of a hydrogen atom in the absence of the external field.We point out that Ĥ1 ( P, p, R, ) corresponds to couplings of the bare electron and proton masses as well as their kinetic and potential energies with the gravitational field (1).The Hamiltonians Ĥ2 (p, r) and Ĥ3 ( P, p, R, ) describe the tidal effects.Note that, in the previous section, we have semiquantitatively derived the Hamiltonian ( 5) and (6).Below, we strictly derive it from the more general Hamiltonian (8)- (12).First, we use the approximation, where   /  ≫ 1, and, thus, we have  =   .This allows us to consider proton as a heavy classical particle.We can fix its position, R = const, in coordinate system, corresponding to the source of the gravitational field (1), by putting P = 0 in the Hamiltonian ( 8)- (12).Therefore, we can disregard center of mass momentum and center of mass kinetic energy.Moreover, as seen from ( 12), Ĥ3 ( P, p, r) = 0 in this case.Now, let us estimate the first tidal term (11) in the Hamiltonian.We recall that |g| ≃ ||/ 0 .It is important that |r| ∼ ℏ/|p| ∼   and p 2 /(2  ) ∼  2 /  in a hydrogen atom.These allow us to evaluate the Hamiltonian (11) as  2 ∼ (  / 0 )(/ 2 )( 2 /  ) ∼ 10 −17 (/ 2 )( 2 /  ), which is 10 −17 smaller than  1 ∼ (/ 2 )( 2 /  ).Therefore, we can also disregard the first tidal term (11) in the total Hamiltonian ( 8)- (12).As a result, the Hamiltonian ( 8)-( 12) can be rewritten in a familiar way: where we place the proton at the point R = .Thus, we can make a conclusion that the Hamiltonian ( 13)-( 15), derived in this section, exactly coincides with the Hamiltonian, semiquantitatively derived by us earlier [2,[5][6][7][8] [see ( 5), ( 6)].Now, suppose that spacecraft moves proton from a hydrogen atom with constant and small velocity,  ≪ ; then the second tidal term (12) in the total electron Hamiltonian is not zero.Nevertheless, it is easy to show that it can be estimated as  3 ∼ (  / 0 )(/ 2 )( 2 /  ) ∼ 10 −17 (/ 2 )( 2 /  ) and, thus, can be omitted.As a result, in adiabatic approximation, we obtain from (15) the time-dependent perturbation (7).

What Is Right and What Is Wrong?
As earlier as in [5], we concluded that the effect suggested by us was very general.In particular, we proposed [5] to use it not only in atomic physics, but also in condensed matter physics [5,10], nuclear physics [1,5], and elementary particle physics [1,5].Here, we recall the physical meaning of the effect.Some quantum macroscopic system is placed in spacecraft and dragged with small constant velocity in an external gravitational field.In this case, due to nonhomogeneous squeezing of space by the field, there appear some quantum excitations in the system, which result in emission of photons [2,[5][6][7][8], phonons [10], pions [1], or some other particles.The experimental task is to detect these particles.We pay attention that, in all our previous works [2,[5][6][7][8]10] as well as in the previous sections of the current paper, we consider the case, where center of mass of a composite quantum system is dragged by spacecraft.It is important that it is dragged by means of nongravitational force with constant velocity with respect to source of gravity.We claim that the extension of our effect to free falling bodies, performed in the comment [1], is not legitimate.It is clearly seen from papers [12,13], where examples of a free falling hydrogen atom is considered and the Fermi normal coordinates are used.As stressed in [12,13], the free falling atoms "feel" only second derivative of the metric (1) and, thus, cannot exhibit our effect.This is also true for nuclear versions of a free falling experiment, considered in the comment [1].To summarize our effect does not have to be observed in "free fall" experiments, discussed in [1].Therefore, the central statement of comment [1], that the nucleus experiments contradict our effect [2,[5][6][7][8]10], is incorrect.