CMISRN Computational Mathematics2090-78422090-7834International Scholarly Research Network84325610.5402/2012/843256843256Research ArticleBrouwer's Fixed Point Theorem with Isolated Fixed Points and His Fan TheoremTanakaYasuhitoKarakasidisT.Faculty of EconomicsDoshisha UniversityKamigyo-kuKyoto 602-8580Japandoshisha.ac.jp20122612012201202102011101120112012Copyright © 2012 Yasuhito Tanaka.This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We show that Brouwer’s fixed point theorem with isolated fixed points is equivalent to Brouwer’s fan theorem.

1. Introduction

It is well known that Brouwer's fixed point theorem cannot be constructively proved.

Kellogg et al.  provided a constructive proof of Brouwer's fixed point theorem. But it is not constructive from the view point of constructive mathematics á la Bishop. It is sufficient to say that one-dimensional case of Brouwer's fixed point theorem, that is, the intermediate value theorem is nonconstructive (see [2, 3]).

Sperner's lemma which is used to prove Brouwer's theorem, however, can be constructively proved. Some authors have presented an approximate version of Brouwer's theorem using Sperner's Lemma (see [3, 4]). Thus, Brouwer's fixed point theorem is constructively, in the sense of constructive mathematics á la Bishop, proved in its approximate version.

Recently Berger and Ishihara  showed that the following theorem is equivalent to Brouwer's fan theorem.

Each uniformly continuous function from a compact metric space into itself with at most one fixed point and approximate fixed points has a fixed point.

In this paper we require a more general condition that each uniformly continuous function from a compact metric space into itself may have only isolated fixed points and show that the proposition that such a function has a fixed point is equivalent to Brouwer's fan theorem.

In another paper we have shown that if a uniformly continuous function in a compact metric space satisfies stronger condition, sequential local non-constancy, then without the fan theorem we can constructively show that it has an exact fixed point (see ).

2. Brouwer's Fixed Point Theorem with Isolated Fixed Points and His Fan Theorem

Let X be a compact (totally bounded and complete) metric space, x be a point in X, and consider a uniformly continuous function f from X into itself.

According to [3, 4] f has an approximate fixed point. It means the following, For each  ɛ>0  there exists  xX  such  that  |x-f(x)|<ɛ.

Since ɛ>0 is arbitrary, infxX  |x-f(x)|=0.

The notion that f has at most one fixed point in  is defined as follows.

Definition 1 (at most one fixed point).

For all x,yX, if xy, then f(x)x or f(y)y.

Now we consider a condition that f may have only isolated fixed points. First we recapitulate the compactness of a set in constructive mathematics. We say that X is totally bounded if for each ɛ>0 there exists a finitely enumerable ɛ-approximation to X. (A set S is finitely enumerable if there exist a natural number N and a mapping of the set {1,2,,N} onto S.) An ɛ-approximation to X is a subset of X such that for each xX there exists y in that ɛ-approximation with |x-y|<ɛ. According to Corollary 2.2.12 of , about totally bounded set we have the following result.

Lemma 2.

If X is totally bounded, for each ɛ>0 there exist totally bounded sets H1,,Hn, each of diameter less than or equal to ɛ, such that X=i=1nHi.

Since infxX|x-f(x)|=0, we have infxHi|x-f(x)|=0 for some HiX such that X=i=1nHi.

The definition that a function may have only isolated fixed points is as follows.

Definition 3 (isolated fixed points).

There exists ɛ¯>0 with the following property. For each ɛ>0 less than or equal to ɛ¯, there exist totally bounded sets H1,,Hn, each of diameter less than or equal to ɛ, such that X=i=1nHi, and in each Hi if xy, then f(x)x or f(y)y.

In each Hi, f has at most one fixed point. Now we show the following lemma, which is based on Lemma 2 of .

Lemma 4.

Let f be a uniformly continuous function from X into itself. Assume infxHif(x)=0 for some HiX defined above. If the following property holds:

for each ɛ>0 there exists δ>0 such that if x,yHi, |f(x)-x|δ and |f(y)-y|δ, then |x-y|ɛ.

Then, there exists a point zHi such that f(z)=z, that is, f has a fixed point.

Proof.

Choose a sequence (xn)n1 in Hi such that |f(xn)-xn|0. Compute N such that |f(xn)-xn|<δ for all nN. Then, for m,nN we have |xm-xn|ɛ. Since ɛ>0 is arbitrary, (xn)n1 is a Cauchy sequence in Hi and converges to a limit zHi. The continuity of f yields |f(z)-z|=0, that is, f(z)=z.

Let Y={0,1}, the set of all binary sequences, {0,1}n with a finite natural number n be the set of finite binary sequences with length n+1. We write x,y,, for the elements (xn)n0,(yn)n0, of Y. Also for each xY and each natural number n we write x¯(n)=(x0,x1,,xn-1).Y is compact under the metric defined by (see [2, 8]) |x-y|=inf{2-n:x¯(n)=y¯(n)}.

Let B be a set of finite binary sequences. B is

detachable if xY    n(x¯(n)Bx¯(n)B);

a bar if xY    n(x¯(n)B);

a uniform bar if       N    xY    nN(x¯(n)B).

In  the following lemma has been proved (their Lemma 4).

Lemma 5.

Let Y={0,1}, and B a detachable bar for Y. Then, for each xY, σ(x)=inf{n:x¯(n)B}   exists, and the mapping x4-σ(x) is uniformly continuous in Y.

Brouwer's fan theorem is as follows.

Theorem 6.

Every detachable bar for {0,1} is a uniform bar.

It has been shown in [2, 5] that this theorem is equivalent to the following theorem.

Theorem 7.

Every positive-valued uniformly continuous function on a compact metric space has positive infimum.

Now, according to the Proof of Theorem 5 in  and the Proof of Proposition in , we show the following result.

Theorem 8.

Brouwer's fixed point theorem with isolated fixed points in a compact metric space is equivalent to Brouwer's fan theorem.

Proof.

(1) Assume that each uniformly continuous function from a compact metric space into itself with isolated fixed points has a fixed point. It implies that each uniformly continuous function from a compact metric space into itself with at most one fixed point has a fixed point. Consider Y={0,1} and a function φ:YY. Let xY, and T be an infinite tree with at most one infinite path (A tree is a detachable set in {0,1} which is closed under restriction.) and define φ(x)n={xnif  x¯(n)T,1-xnif  x¯(n)T.       Since  x¯(n)=y¯(n) implies φ(x)¯(n)=φ(y)¯(n), φ is uniformly continuous. Thus, φ has a fixed point. From the definition of φ its fixed print is an infinite branch. Thus, T has an infinite branch. Let B be a detachable bar and set  B={x:n(x¯(n)B)}. Then, B is also a detachable bar. For x=(x0,,xn-1) and y=(y0,,ym-1) set   x*y=(x0,,xn-1,y0,,ym-1). If xB, then x*yB. Consider a tree {0,1}B. Define for each n a un{0,1}n by the following procedure. If {0,1}nB, let un be any element of {0,1}nB. If  {0,1}nB, let k be the largest number such that {0,1}kB and define un=uk*(0,,0)n-k    times. Set  T=({0,1}NB){un:{0,1}nB}. Then, T is an infinite tree since it contains each un. For all x with length n we have xBTx=un. Let x,y{0,1} and suppose xy. Then, there is n such that x¯(n)B, y¯(n)B, and x¯(n)y¯(n). Thus, x¯(n)un or y¯(n)un, and so x¯(n)T or y¯(n)T. Therefore, T has at most one infinite branch. From the argument above it has an infinite branch x. Since B is a bar, there is m such that x¯(m)B. Thus, x¯(m)BT, and so x¯(m)=um. Therefore, {0,1}mB, and B is a uniform bar. It means that B is also a uniform bar.

(2) Assume Brouwer's Fan theorem. Consider a compact metric space X and a uniformly continuous function f from X into itself with isolated fixed points. Then, |x-f(x)| is uniformly continuous. Let xX, and Hi, i=1,,n be totally bounded subsets of X, each of diameter less than or equal to ɛ¯ in Definition 3, such that X=i=1nHi. Given ɛ>0 assume that the set   K={(x,y)Hi×Hi:|x-y|ɛ}, is nonempty and compact (see Theorem 2.2.13 of ). For x,yHi let F(x,y)=|x-f(x)|+|y-f(y)|. Then, F is uniformly continuous and positive-valued on K. So, by Theorem 7          0<δ=13inf{F(x,y):(x,y)K}. For each (x,y)K we have |x-f(x)|+|y-f(y)|=F(x,y)>2δ. Thus, either |x-f(x)|>δ or |y-f(y)|>δ. It follows that if x,yHi, |x-f(x)|δ and |y-f(y)|δ, then (x,y)K and so |x-y|ɛ. Then, from Lemma 4 there exists a fixed point of f in Hi*X such that infxHi*|x-f(x)|=0. Thus, Brouwer's fan theorem implies his fixed point theorem for uniformly continuous functions with isolated fixed points.

Acknowledgment

This research was partially supported by the Ministry of Education, Science, Sports and Culture of Japan, Grant-in-Aid for Scientific Research (C), 20530165.

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