A new concept of the c-distance in cone metric space has been introduced recently in 2011. The aim of this paper is to extend and generalize some fixed point theorems on c-distance in cone metric space.

1. Introduction

The concept of cone metric spaces is a generalization of metric spaces, where each pair of points is assigned to a member of a real Banach space with a cone, for new results on cone metric spaces see . This cone naturally induces a partial order in the Banach spaces. The concept of cone metric space was introduced in the work of Huang and Zhang , where they also established the Banach contraction mapping principle in this space. Then, several authors have studied fixed point problems in cone metric spaces. Some of these works are noted in .

In , Cho et al. introduced a new concept of the c-distance in cone metric spaces and proved some fixed point theorems in ordered cone metric spaces. This is more general than the classical Banach contraction mapping principle.

In , Sintunavarat et al. extended and developed the Banach contraction theorem on c-distance of Cho et al. . They gave some illustrative examples of the main results. Their results improve, generalize, and unify the results of Cho et al.  and some results of the fundamental metrical fixed point theorems in the literature.

In this paper we proved some fixed point theorems for c-distance in cone metric space. These theorems extend and develop some theorems in literature on c-distance of Cho et al.  in cone metric space.

The following theorems are the main results given in [7, 14, 16].

Theorem 1.1 (see [<xref ref-type="bibr" rid="B12">16</xref>]).

Let (X,d) be a complete cone metric space. Suppose that the mapping f:XX satisfies the contractive condition: d(fx,fy)kd(x,y), for all x,yX, where k[0,1) is a constant. Then f has a unique fixed point in X and for any xX, iterative sequence {fnx} converges to the fixed point.

Theorem 1.2 (see [<xref ref-type="bibr" rid="B2">7</xref>]).

Let (X,d) be a complete cone metric space and P be a normal cone with normal constant K. Suppose that the mapping f:XX satisfies the contractive condition: d(fx,fy)k(d(fx,x)+d(fy,y)), for all x,yX, where k[0,1/2) is a constant. Then f has a unique fixed point in X and for any xX, iterative sequence {fnx} converges to the fixed point.

Theorem 1.3 (see [<xref ref-type="bibr" rid="B2">7</xref>]).

Let (X,d) be a complete cone metric space and P be a normal cone with normal constant K. Suppose that the mapping f:XX satisfies the contractive condition: d(fx,fy)k(d(fx,y)+d(fy,x)), for all x,yX, where k[0,1/2) is a constant. Then f has a unique fixed point in X and for any xX, iterative sequence {fnx} converges to the fixed point.

Theorem 1.4 (see [<xref ref-type="bibr" rid="B9">14</xref>]).

Let (X,) be a partially ordered set and suppose that (X,d) is a complete cone metric space. Let q is a c-distance on X and f:XX be a continous and nondecreasing mapping with respect to . Suppose that the following two assertions hold:

there exist α,β,γ>0 with α+β+γ<1 such that q(fx,fy)αq(x,y)+βq(x,fx)+γq(y,fy), for all x,yX with yx,

there exists x0X such that x0fx0.

Then f has a fixed point x*X. If v=fv then q(v,v)=θ.

2. Preliminaries

Let E be a real Banach space and θ denote to the zero element in E. A cone P is a subset of E such that

P is nonempty set closed and P{θ},

if a,b are nonnegative real numbers and x,yP then ax+byP,

xP and -xP imply that x=θ.

For any cone PE, the partial ordering with respect to P is defined by xy if and only if y-xP. The notation of stands for xy but xy. Also, we used xy to indicate that y-xintP, where intP denotes the interior of P. A cone P is called normal if there exists a number K such that θxyxKy, for all x,yE. The least positive number K satisfying the above condition is called the normal constant of P.

Definition 2.1 (see [<xref ref-type="bibr" rid="B2">7</xref>]).

Let X be a nonempty set and E be a real Banach space equipped with the partial ordering with respect to the cone P. Suppose that the mapping d:X×XE satisfies the following conditions:

θd(x,y) for all x,yX and d(x,y)=θ if and only if x=y,

d(x,y)=d(y,x) for all x,yX,

d(x,y)d(x,y)+d(y,z) for all x,y,zX.

Then d is called a cone metric on X and (X,d) is called a cone metric space.

Definition 2.2 (see [<xref ref-type="bibr" rid="B2">7</xref>]).

Let (X,d) be a cone metric space, {xn} be a sequence in X, and xX.

For all cE with θc, if there exists a positive integer N such that d(xn,x)c for all n>N, then xn is said to be convergent and x is the limit of {xn}. We denote this by xnx.

For all cE with θc, if there exists a positive integer N such that d(xn,xm)c for all n,m>N, then {xn} is called a Cauchy sequence in X.

A cone metric space (X,d) is called complete if every Cauchy sequence in X is convergent.

Lemma 2.3 (see [<xref ref-type="bibr" rid="B11">17</xref>]).

If E is a real Banach space with a cone P and aλa, where aP and 0<λ<1, then a=θ.

If cintP, θan and anθ, then there exists a positive integer N such that anc for all nN.

Next we give the notation of c-distance on a cone metric space which is a generalization of ω-distance of Kada et al.  with some properties.

Definition 2.4 (see [<xref ref-type="bibr" rid="B9">14</xref>]).

Let (X,d) is a cone metric space. A function q:X×XE is called a c-distance on X if the following conditions hold:

θq(x,y) for all x,yX,

q(x,y)q(x,y)+q(y,z) for all x,y,zX,

for each xX and n1, if q(x,yn)u for some u=uxP, then q(x,y)u whenever {yn} is a sequence in X converging to a point yX,

for all cE with θc, there exists eE with θe such that q(z,x)e and q(z,y)e imply d(x,y)c.

Example 2.5 (see [<xref ref-type="bibr" rid="B9">14</xref>]).

Let E= and P=(xE:x0). let X=[0,) and define a mapping d:X×XE by d(x,y)=|x-y| for all x,yX. then (X,d) is a cone metric space. define a mapping q:X×XE by q(x,y)=y for all x,yX. Then q is a c-distance on X.

Lemma 2.6 (see [<xref ref-type="bibr" rid="B9">14</xref>]).

Let (X,d) be a cone metric space and q is a c-distance on X. Let {xn} and {yn} be sequences in X and x,y,zX. Suppose that un is a sequences in P converging to θ. Then the following hold:

If q(xn,y)un and q(xn,z)un, then y=z,

If q(xn,yn)un and q(xn,z)un, then {yn} converges to z,

If q(xn,xm)un for m>n, then {xn}  is a Cauchy sequence in X,

If q(y,xn)un, then {xn} is a Cauchy sequence in X.

Remark 2.7 (see [<xref ref-type="bibr" rid="B9">14</xref>]).

q(x,y)=q(y,x) does not necessarily for all x,yX.

q(x,y)=θ is not necessarily equivalent to x=y for all x,yX.

3. Main Results

In this section we prove some fixed point theorems using c-distance in cone metric space. In whole paper cone metric space is over nonnormal cone with nonempty interior.

Theorem 3.1.

Let (X,d) be a complete cone metric space and q is a c-distance on X. Suppose that the mapping f:XX satisfies the contractive condition: q(fx,fy)kq(x,y), for all x,yX, where k[0,1) is a constant. Then f has a fixed point x*X and for any xX, iterative sequence {fnx} converges to the fixed point. If v=fv then q(v,v)=θ. The fixed point is unique.

Proof.

Choose x0X. Set x1=fx0,x2=fx1=f2x0,,xn+1=fxn=fn+1x0. We have: q(xn,xn+1)=q(fxn-1,fxn)kq(xn-1,xn)k2q(xn-2,xn-1)knq(x0,x1). Let m>n1. Then it follows that q(xn,xm)q(xn,xn+1)+q(xn+1,xn+2)++q(xm-1,xm)(kn+kn+1++km-1)q(x0,x1)kn1-kq(x0,x1).

Thus, Lemma 2.6 shows that {xn} is a Cauchy sequence in X. Since X is complete, there exists x*X such that xnx* as n. By (q3) we have: q(xn,x*)kn1-kq(x0,x1).

On the other hand, q(xn,fx*)=q(fxn-1,fx*)kq(xn-1,x*)kkn-11-kq(x0,x1)=kn1-kq(x0,x1).

By Lemma 2.6 part 1, (3.4) and (3.5), we have x*=fx*. Thus, x* is a fixed point of f.

Suppose that v=fv, then we have the following: q(v,v)=q(fv,fv)kq(v,v). Since k<1, Lemma 2.3 show that q(v,v)=θ.

Finally suppose there is another fixed point y* of f, then we have the following: q(x*,y*)=q(fx*,fy*)kq(x*,y*). Since k<1, Lemma 2.3 show that q(x*,y*)=θ and also we have q(x*,x*)=θ. Hence by Lemma 2.6 part 1, x*=y*. Therefore the fixed point is unique.

Corollary 3.2.

Let (X,d) be a complete cone metric space and q is a c-distance on X. Suppose that the mapping f:XX satisfies the contractive condition: q(fnx,fny)kd(x,y), for all x,yX, where k[0,1) is a constant. Then f has a unique fixed point x*X. If v=fv then q(v,v)=θ.

Proof.

From Theorem 3.1  fn has a unique fixed point x*. But fn(fx*)=f(fnx*)=f(x*), so f(x*) is also a fixed point of fn. Hence x*=fx*. Thus, x* is a fixed point of f. Since the fixed point of f is also fixed point of fn, the fixed point of f is unique.

Suppose that v=fv. From above the fixed point of f is also fixed point of fn, then we have the following: q(v,v)=q(fv,fv)=q(fnv,fnv)kq(v,v). Since k<1, Lemma 2.3 show that q(v,v)=θ.

The following result is generalized from Theorem 1.4. We prove a fixed point theorem and we do not require that X is a partially ordered set.

Theorem 3.3.

Let (X,d) be a complete cone metric space and q is a c-distance on X. Suppose that the mapping f:XX is continuous and satisfies the contractive condition: q(fx,fy)kq(x,y)+lq(x,fx)+rq(y,fy), for all x,yX, where k, l, r are nonnegative real numbers such that k+l+r<1. Then f has a fixed point x*X and for any xX, iterative sequence {fnx} converges to the fixed point. If v=fv then q(v,v)=θ. The fixed point is unique.

Proof.

Choose x0X. Set x1=fx0,x2=fx1=f2x0,,xn+1=fxn=fn+1x0. We have the following: q(xn,xn+1)=q(fxn-1,fxn)kq(xn-1,xn)+lq(xn-1,fxn-1)+rq(xn,fxn)=kq(xn-1,xn)+lq(xn-1,xn)+rq(xn,xn+1). So q(xn,xn+1)k+l1-rq(xn-1,xn)=hq(xn-1,xn), where h=(k+l)/(1-r)<1.

Let m>n1. Then it follows that q(xn,xm)q(xn,xn+1)+q(xn+1,xn+2)++q(xm-1,xm)(hn+hn+1++hm-1)q(x0,x1)hn1-hq(x0,x1).

Thus, Lemma 2.6 shows that {xn} is a Cauchy sequence in X. Since X is complete, there exists x*X such that xnx* as n. Since f is continuous, then x*=limxn+1=limf(xn)=f(limxn)=f(x*). Therefore x* is a fixed point of f.

Suppose that v=fv, then we have q(v,v)=q(fv,fv)kq(v,v)+lq(v,fv)+rq(v,fv)=(k+l+r)q(v,v), since k+l+r<1, Lemma 2.3 show that q(v,v)=θ.

Finally, suppose that, there is another fixed point y* of f, then we have the following: q(x*,y*)=q(fx*,fy*)kq(x*,y*)+lq(x*,fx*)+rq(y*,fy*)=kq(x*,y*)+lq(x*,x*)+rq(y*,y*)=kq(x*,y*)kq(x*,y*)+lq(x*,y*)+rq(x*,y*)=(k+l+r)q(x*,y*). Since k+l+r<1<1, Lemma 2.3 shows that q(x*,y*)=θ and also we have q(x*,x*)=θ. Hence by Lemma 2.6 part 1, x*=y*. Therefore the fixed point is unique.

If k=0 and r=l, then we have the following result.

Corollary 3.4.

Let (X,d) be a complete cone metric space and q is a c-distance on X. Suppose that the mapping f:XX is continuous and satisfies the contractive condition: q(fx,fy)l(q(x,fx)+q(y,fy)), for all x,yX,where l[0,1/2) is a constant. Then f has a fixed point x*X and for any xX, iterative sequence {fnx} converges to the fixed point. If v=fv then q(v,v)=θ. The fixed point is unique.

Finally, we provide another result and we do not require that f is continuous.

Theorem 3.5.

Let (X,d) be a complete cone metric space and q is a c-distance on X. Suppose that the mapping f:XX satisfies the contractive condition: (1-r)q(fx,fy)kq(x,fy)+lq(x,fx), for all x,yX, where k,l,r are nonnegative real numbers such that 2k+l+r<1. Then f has a fixed point x*X and for any xX, iterative sequence {fnx} converges to the fixed point. If v=fv then q(v,v)=θ. The fixed point is unique.

Proof.

Choose x0X. Set x1=fx0,x2=fx1=f2x0,,xn+1=fxn=fn+1x0. Observe that (1-r)q(fx,fy)kq(x,fy)+lq(x,fx), equivalently q(fx,fy)kq(x,fy)+lq(x,fx)+rq(fx,fy). Then we have: q(xn,xn+1)=q(fxn-1,fxn)kq(xn-1,fxn)+lq(xn-1,fxn-1)+rq(fxn-1,fxn)=kq(xn-1,xn+1)+lq(xn-1,xn)+rq(xn,xn+1)kq(xn-1,xn)+kq(xn,xn+1)+lq(xn-1,xn)+rq(xn,xn+1). So, q(xn,xn+1)k+l1-k-rq(xn-1,xn)=hq(xn-1,xn), where h=(k+l)/(1-k-r)<1.

Let m>n1. Then it follows that q(xn,xm)q(xn,xn+1)+q(xn+1,xn+2)++q(xm-1,xm)(hn+hn+1++hm-1)q(x0,x1)hn1-hq(x0,x1).

Thus, Lemma 2.6 shows that {xn} is a Cauchy sequence in X. Since X is complete, there exists x*X such that xnx* as n.

By (q3) we have: q(xn,x*)hn1-hq(x0,x1).

On the other hand, q(xn,fx*)=q(fxn-1,fx*)kq(xn-1,fx*)+lq(xn-1,fxn-1)+rq(fxn-1,fx*)=kq(xn-1,fx*)+lq(xn-1,xn)+rq(xn,xn+1)kq(xn-1,xn)+kq(xn,fx*)+lq(xn-1,xn)+rq(xn,fx*). So, q(xn,fx*)k+l1-k-rq(xn-1,xn)k+l1-k-rhn-1q(x0,x1)=hhn-1q(x0,x1)=hnq(x0,x1)hn1-hq(x0,x1).

By Lemma 2.6 part 1, (3.20) and (3.22), we have x*=fx*. Thus, x* is a fixed point of f.

Suppose that v=fv, then we have q(v,v)=q(fv,fv)kq(v,fv)+lq(v,fv)+rq(v,fv)=kq(v,v)+lq(v,v)+rq(v,v)kq(v,v)+kq(v,v)+lq(v,v)+rq(v,v)=(2k+l+r)q(v,v). Since 2k+l+r<1, Lemma 2.3 shows that q(v,v)=θ.

Finally, suppose that, there is another fixed point y* of f, then we have q(x*,y*)=q(fx*,fy*)kq(x*,fy*)+lq(x*,fx*)+rq(fx*,fy*)kq(x*,fy*)+kq(x*,fy*)+lq(x*,fx*)+rq(fx*,fy*)=kq(x*,y*)+kq(x*,y*)+lq(x*,x*)+rq(x*,y*)=kq(x*,y*)+kq(x*,y*)+rq(x*,y*)kq(x*,y*)+kq(x*,y*)+lq(x*,y*)+rq(x*,y*)=(2k+l+r)q(x*,y*).

Since 2k+l+r<1, Lemma 2.3 shows that q(x*,y*)=θ and also we have q(x*,x*)=θ. Hence by Lemma 2.6 part 1, x*=y*. Therefore the fixed point is unique.

Example 3.6.

Consider Example 2.5. Define the mapping f:XX by f(3/4)=1/4 and fx=x/2 for all xX with x3/4. Since d(f(1),f(3/4))=d(1,3/4), there is not k[0,1) such that d(fx,fy)kd(x,y). Since Theorem  2.3 of Rezapour and Hamlbarani  cannot be applied to this example on cone metric space. To check this example on c-distance we have:

If x=y=3/4, then we have the following.

q(f(34),f(34))=f(34)=14k34=kq(34,34)with  k=23.

If xy3/4, then we have q(fx,fy)=y2kq(x,y)with  k=23.

If x=3/4,y3/4, then we have q(f(34),fy)=y2kq(34,y)with  k=23.

If x3/4,y=3/4, then we have q(fx,f(34))=f(34)=14k34=kq(x,34)with  k=23.

Hence q(fx,fy)kq(x,y) for all xX. Therefore, the condition of Theorem 3.1 are satisfied and then f has a unique fixed point x=0, f(0)=0 with q(0,0)=0.

Acknowledgments

The authors Zaid Mohammed Fadail and Abd Ghafur Bin Ahmad would like to acknowledge the financial support received from Universiti Kebangsaan Malaysia under the research Grant ERGS/1/2011/STG/UKM/01/13. Zoran Golubović is thankful to the Ministry of Science and Technological Development of Serbia. The authors thank the referee for his/her careful reading of the paper and useful suggestions.